2008 AMC 12B Problem 16

Attempt Problem 16 of the 2008 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

A rectangular floor measures aa feet by bb feet, where aa and bb are positive integers with b>a.b \gt a. An artist paints a rectangle on the floor with the sides of the rectangle parallel to the sides of the floor. The unpainted part of the floor forms a border of width 11 foot around the painted rectangle and occupies half the area of the entire floor. How many possibilities are there for the ordered pair (a,b)?(a, b)?

11

22

33

44

55

Answer: B
Concepts:areaSimon’s Favorite Factoring Trickfactor
Difficulty rating: 1660
Solution:

The painted rectangle measures (a2)(a - 2) by (b2)(b - 2) and has half the area of the floor, so ab=2(a2)(b2). ab = 2(a - 2)(b - 2).

Expanding gives 0=ab4a4b+8,0 = ab - 4a - 4b + 8, and adding 88 yields (a4)(b4)=8.(a - 4)(b - 4) = 8.

With b>a>0,b \gt a \gt 0, the only valid factor pairs of 88 are (a4,b4)=(1,8)(a - 4, b - 4) = (1, 8) and (2,4),(2, 4), giving (a,b)=(5,12)(a, b) = (5, 12) and (6,8).(6, 8).

There are 22 possibilities.

Thus, the correct answer is B.

← Problem 15#15
Full Exam

Problem 16 in Other Years