2006 AMC 12B Problem 2

Attempt Problem 2 of the 2006 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

For real numbers xx and y,y, define x♠y=(x+y)(x−y).x \spadesuit y = (x + y)(x - y). What is 3♠(4♠5)?3 \spadesuit (4 \spadesuit 5)?
−72-72
−27-27
−24-24
2424
7272
Answer: A
Concepts:custom operationdifference of squares
Small hint:
Note that x♠y=x2−y2x \spadesuit y = x^2 - y^2
Big hint:
Evaluate the inner 4♠54 \spadesuit 5 first, then apply the operation again
Solution:
Since x♠y=x2−y2,x \spadesuit y = x^2 - y^2, the inner value is 4♠5=16−25=−9.4 \spadesuit 5 = 16 - 25 = -9.
Then 3♠(−9)=32−(−9)23 \spadesuit (-9) = 3^2 - (-9)^2 =9−81=−72.= 9 - 81 = -72.
Thus, the correct answer is A.
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