2005 AMC 12B Problem 8

Attempt Problem 8 of the 2005 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

For how many values of aa is it true that the line y=x+ay = x + a passes through the vertex of the parabola y=x2+a2?y = x^2 + a^2?
00
11
22
1010
infinitely many
Answer: C
Concepts:parabolaquadratic
Small hint:
The vertex of y=x2+a2y = x^2 + a^2 is (0,a2)(0, a^2)
Big hint:
Substitute the vertex into the line to get a2=aa^2 = a
Solution:
The vertex of the parabola y=x2+a2y = x^2 + a^2 is (0,a2).(0, a^2).
The line y=x+ay = x + a passes through it exactly when a2=0+a,a^2 = 0 + a, that is a2−a=0.a^2 - a = 0.
This gives a=0a = 0 or a=1,a = 1, so there are 22 values.
Thus, the correct answer is C.
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