2004 AMC 12B Problem 17

Attempt Problem 17 of the 2004 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 12B solutions, or check the answer key.

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17.

For some real numbers aa and b,b, the equation 8x3+4ax2+2bx+a=08x^3 + 4ax^2 + 2bx + a = 0 has three distinct positive roots. If the sum of the base-22 logarithms of the roots is 5,5, what is the value of a?a?
−256-256
−64-64
−8-8
6464
256256
Answer: A
Concepts:Vieta’s Formulaslogarithm
Small hint:
The sum of log⁡2\log_2 of the roots equals log⁡2\log_2 of their product
Big hint:
For 8x3+⋯+a,8x^3 + \cdots + a, the product of the roots is −a8-\dfrac{a}{8}
Solution:
The sum of the base-22 logarithms is log⁡2(r1r2r3)=5,\log_2(r_1 r_2 r_3) = 5, so r1r2r3=25=32.r_1 r_2 r_3 = 2^5 = 32. By Vieta’s formulas on 8x3+4ax2+2bx+a,8x^3 + 4ax^2 + 2bx + a, the product of the roots is −a8.-\dfrac{a}{8}. Thus −a8=32,-\dfrac{a}{8} = 32, giving a=−256.a = -256.
Thus, the correct answer is A.
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