2004 AMC 12A Problem 16

Attempt Problem 16 of the 2004 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 12A solutions, or check the answer key.

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16.

The set of all real numbers xx for which log⁡2004(log⁡2003(log⁡2002(log⁡2001x)))\small \log_{2004}(\log_{2003}(\log_{2002}(\log_{2001} x))) is defined is {x∣x>c}.\{x \mid x \gt c\}. What is the value of c?c?
00
200120022001^{2002}
200220032002^{2003}
200320042003^{2004}
2001200220032001^{2002^{2003}}
Answer: B
Concepts:logarithminequality
Small hint:
Work from the outside in: each logarithm requires its argument to be positive
Big hint:
log⁡2004(⋯ )\log_{2004}(\cdots) is defined only when log⁡2003(⋯ )>0,\log_{2003}(\cdots) \gt 0, i.e. the next argument exceeds 11
Solution:
The expression is defined if and only if log⁡2003(log⁡2002(log⁡2001x))>0,\log_{2003}(\log_{2002}(\log_{2001} x)) \gt 0, that is, log⁡2002(log⁡2001x)>1.\log_{2002}(\log_{2001} x) \gt 1.
This holds if and only if log⁡2001x>2002,\log_{2001} x \gt 2002, which is equivalent to x>20012002.x \gt 2001^{2002}.
Therefore c=20012002.c = 2001^{2002}.
Thus, the correct answer is B.
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