1997 AMC 12 Problem 8

Attempt Problem 8 of the 1997 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

Mientka Publishing Company prices its best seller Where’s Walter? as follows: C(n)={12n,1≤n≤24,11n,25≤n≤48,10n,49≤n, C(n)= \begin{cases} 12n, & 1\le n\le24,\\ 11n, & 25\le n\le48,\\ 10n, & 49\le n, \end{cases} where nn is the number of books ordered, and C(n)C(n) is the cost in dollars of nn books. Notice that 2525 books cost less than 2424 books. For how many values of nn is it cheaper to buy more than nn books than to buy exactly nn books?
33
44
55
66
88
Answer: D
Concepts:piecewise functionsinequalities
Small hint:
Only the two price-break points can make a larger order cheaper
Big hint:
Compare C(n)C(n) with C(25)C(25) near the first break and with C(49)C(49) near the second
Solution:
At the first break, C(25)=275C(25)=275 is below C(23)=276C(23)=276 and C(24)=288,C(24)=288, giving n=23n=23 and n=24.n=24. At the second, C(49)=490C(49)=490 is below C(n)=11nC(n)=11n for n=45,n=45, n=46,n=46, n=47,n=47, n=48.n=48. No other nn works because each piece increases. There are 2+4=6,2+4=6, so D is correct.
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