1994 AMC 12 Problem 26

Attempt Problem 26 of the 1994 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 12 solutions, or check the answer key.

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26.

A regular polygon of mm sides is exactly enclosed (no overlaps, no gaps) by mm regular polygons of nn sides each. (Shown here for m=4,m=4, n=8.n=8.) If m=10,m=10, what is the value of n?n?
55
66
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2020
2626
Answer: A
Concepts:regular polygonsinterior anglesangle sums
Small hint:
At each vertex of the inner polygon, one mm-gon angle and two nn-gon angles fill 360∘360^\circ
Big hint:
Use the regular kk-gon interior angle 180∘(1−2k)180^\circ(1-\frac{2}{k})
Solution:
At a vertex of the inner polygon, its interior angle and two angles from the surrounding polygons total 360∘.360^\circ. Thus 180∘(1−2m)+2⋅180∘(1−2n)=360∘. \begin{gathered} 180^\circ\left(1-\frac2m\right) \\ {}+2\cdot180^\circ\left(1-\frac2n\right)\\ {}=360^\circ. \end{gathered} This simplifies to 1m+2n=12.\frac{1}{m}+\frac{2}{n}=\frac{1}{2}. With m=10,m=10, we get 2n=25,\frac{2}{n}=\frac{2}{5}, so n=5.n=5. Thus the correct answer is A.
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