1994 AMC 12 Problem 12

Attempt Problem 12 of the 1994 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

If i2=−1,i^2=-1, then (i−i−1)−1= \left(i-i^{-1}\right)^{-1}=
00
−2i-2i
2i2i
−i2-\frac{i}{2}
i2\frac{i}{2}
Answer: D
Concepts:complex numbersreciprocals
Small hint:
Use i−1=−ii^{-1}=-i
Big hint:
After simplifying the parentheses, rationalize 12i\frac{1}{2i}
Solution:
Because i−1=−i,i^{-1}=-i, (i−i−1)−1=(i+i)−1=12i=−i2. \begin{aligned} \left(i-i^{-1}\right)^{-1} &=(i+i)^{-1}\\ &=\frac1{2i}\\ &=-\frac i2. \end{aligned} Thus the correct answer is D.
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