1993 AMC 12 Problem 12

Attempt Problem 12 of the 1993 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

If f(2x)=22+xf(2x)=\frac{2}{2+x} for all x>0,x\gt0, then 2f(x)=2f(x)=
21+x\frac{2}{1+x}
22+x\frac{2}{2+x}
41+x\frac{4}{1+x}
42+x\frac{4}{2+x}
84+x\frac{8}{4+x}
Answer: E
Concepts:function substitutionrational expressions
Small hint:
To obtain f(x),f(x), replace the given input variable by x2\frac{x}{2}
Big hint:
Simplify 2f(x)=2(22+x2)2f(x)=2\left(\frac{2}{2+\frac{x}{2}}\right)
Solution:
Replacing the given xx by x2\frac{x}{2} yields f(x)=22+x2=44+x. f(x)=\frac{2}{2+\frac{x}{2}}=\frac{4}{4+x}. Therefore 2f(x)=84+x.2f(x)=\frac{8}{4+x}. Thus the correct answer is E.
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