1988 AMC 12 Problem 2

Attempt Problem 2 of the 1988 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

Triangles ABCABC and XYZXYZ are similar, with AA corresponding to XX and BB to Y.Y. If AB=3,AB=3, BC=4,BC=4, and XY=5,XY=5, then YZYZ is
3343\frac34
66
6146\frac14
6236\frac23
88
Answer: D
Concepts:similar trianglesscale factorproportions
Small hint:
Match ABAB with XYXY and BCBC with YZYZ
Big hint:
Use the scale factor from the first triangle to the second
Solution:
The scale factor is XYAB=53.\frac{XY}{AB}=\frac{5}{3}. Therefore YZ=(53)BC=(53)(4)YZ=(\frac{5}{3})BC=(\frac{5}{3})(4) and YZ=203=623.YZ=\frac{20}{3}=6\frac23.
Thus the correct answer is D.
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