1987 AMC 12 Problem 28

Attempt Problem 28 of the 1987 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1987 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

28.

Let a,a, b,b, c,c, dd be real numbers. Suppose that all the roots of z4+az3+bz2+cz+d=0 z^4+az^3+bz^2+cz+d=0 are complex numbers lying on a circle in the complex plane centered at 0+0i0+0i and having radius 1.1. The sum of the reciprocals of the roots is necessarily
aa
bb
cc
−a-a
−b-b
Answer: D
Concepts:complex conjugatesunit circleVieta’s formulas
Small hint:
For a complex number rr on the unit circle, compare 1r\frac{1}{r} with r‾\overline r
Big hint:
Real polynomial coefficients make the sum of the roots real
Solution:
If ∣r∣=1,|r|=1, then 1r=r‾.\frac{1}{r}=\overline r. Therefore the sum of the reciprocals is the conjugate of the sum of the roots. By Vieta’s formulas, the sum of the roots is −a,-a, which is real. Its conjugate is still −a.-a.
Thus the correct answer is D.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.