1955 AMC 12 Problem 32

Attempt Problem 32 of the 1955 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1955 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

32.

If the discriminant of ax2+2bx+c=0ax^2+2bx+c=0 is zero, then another true statement about a,a, b,b, and cc is that:
they form an arithmetic progression
they form a geometric progression
they are unequal
they are all negative numbers
only bb is negative and aa and cc are positive
Answer: B
Concepts:quadratic discriminantgeometric progression
Small hint:
Set (2b)2−4ac(2b)^2-4ac equal to zero
Big hint:
Compare the resulting relation with the defining tests for arithmetic and geometric progressions
Solution:
A zero discriminant gives (2b)2−4ac=0, (2b)^2-4ac=0, hence b2=ac.b^2=ac. Equivalently, ab=bc\frac{a}{b}=\frac{b}{c} where the ratios are defined, which is the defining relation for a,b,ca,b,c to form a geometric progression.
Thus, the correct answer is B.
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