1955 AMC 12 Problem 32

Attempt Problem 32 of the 1955 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1955 AMC 12 solutions, or check the answer key.

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32.

If the discriminant of ax2+2bx+c=0ax^2+2bx+c=0 is zero, then another true statement about a,a, b,b, and cc is that:

they form an arithmetic progression

they form a geometric progression

they are unequal

they are all negative numbers

only bb is negative and aa and cc are positive

Answer: B
Concepts:quadratic discriminantgeometric progression
Difficulty rating: 1260
Small Hint:

Set (2b)24ac(2b)^2-4ac equal to zero

Big Hint:

Compare the resulting relation with the defining tests for arithmetic and geometric progressions

Solution:

A zero discriminant gives (2b)24ac=0, (2b)^2-4ac=0, hence b2=ac.b^2=ac. Equivalently, ab=bc\frac{a}{b}=\frac{b}{c} where the ratios are defined, which is the defining relation for a,b,ca,b,c to form a geometric progression.

Thus, the correct answer is B.

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Problem 32 in Other Years

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