1953 AMC 12 Problem 17

Attempt Problem 17 of the 1953 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1953 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

A man has part of $4500\$4500 invested at 4%4\% and the rest at 6%.6\%. If his annual return on each investment is the same, the average rate of interest which he realizes on the $4500\$4500 is:
5%5\%
4.8%4.8\%
5.2%5.2\%
4.6%4.6\%
none of these
Answer: B
Concepts:simple interestweighted averageequation
Small hint:
Let xx be the amount invested at 4%4\% and equate the two returns
Big hint:
Solve 0.04x=0.06(4500−x)0.04x=0.06(4500-x), then find the total return
Solution:
Let xx dollars be invested at 4%.4\%. Equal returns give 0.04x=0.06(4500−x), 0.04x=0.06(4500-x), so x=2700.x=2700. Each investment returns $108,\$108, for a total of $216.\$216. The average rate is 2164500=0.048=4.8%. \frac{216}{4500}=0.048=4.8\%.
Thus, the correct answer is B.
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