1953 AMC 12 Problem 14

Attempt Problem 14 of the 1953 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1953 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

Given the larger of two circles with center PP and radius pp and the smaller with center QQ and radius q.q. Draw PQ‾.\overline{PQ}. Which of the following statements is false?
p−qp-q can be equal to PQ‾\overline{PQ}
p+qp+q can be equal to PQ‾\overline{PQ}
p+qp+q can be less than PQ‾\overline{PQ}
p−qp-q can be less than PQ‾\overline{PQ}
none of these
Answer: E
Concepts:circlescenter distancetangency
Small hint:
Interpret the center distance for internal tangency, external tangency, and disjoint circles
Big hint:
For each of the first four statements, try to choose a valid relative position of the circles
Solution:
Internal tangency realizes PQ=p−q,PQ=p-q, and external tangency realizes PQ=p+q.PQ=p+q. Disjoint circles can have PQ>p+q,PQ\gt p+q, and many intersecting or disjoint configurations have PQ>p−q.PQ\gt p-q. Thus each of A through D can occur, so none of them is false.
Therefore, the correct answer is E.
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