1952 AMC 12 Problem 41

Attempt Problem 41 of the 1952 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1952 AMC 12 solutions, or check the answer key.

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41.

Increasing the radius of a cylinder by 66 units increases the volume by yy cubic units. Increasing the altitude of the cylinder by 66 units also increases the volume by yy cubic units. If the original altitude is 2,2, then the original radius is:

22

44

66

6π6\pi

88

Answer: C
Concepts:cylindervolumequadratic
Difficulty rating: 1770
Small Hint:

Let the original radius be rr and write each of the two volume increases

Big Hint:

Equate 2π((r+6)2r2)2\pi((r+6)^2-r^2) and 6πr26\pi r^2

Solution:

With original height 22 and radius r,r, increasing the radius adds 2π((r+6)2r2)=24πr+72π 2\pi\bigl((r+6)^2-r^2\bigr)=24\pi r+72\pi cubic units. Increasing the height by 66 adds 6πr26\pi r^2 cubic units. Equating these gives 6r2=24r+72, 6r^2=24r+72, or r24r12=0.r^2-4r-12=0. Its positive root is r=6.r=6.

Thus, the correct answer is C.

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Problem 41 in Other Years

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