2009 AMC 10B Problem 23

Attempt Problem 23 of the 2009 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

Rachel and Robert run on a circular track. Rachel runs counterclockwise and completes a lap every 9090 seconds, and Robert runs clockwise and completes a lap every 8080 seconds. Both start from the start line at the same time. At some random time between 1010 minutes and 1111 minutes after they begin to run, a photographer standing inside the track takes a picture that shows one-fourth of the track, centered on the starting line. What is the probability that both Rachel and Robert are in the picture?
116\dfrac{1}{16}
18\dfrac18
316\dfrac{3}{16}
14\dfrac14
516\dfrac{5}{16}
Answer: C
Concepts:geometric probabilitydistance rate and time
Small hint:
The picture covers 18\dfrac18 of a lap on each side of the start line
Big hint:
Find each runner’s window of time inside that region during the 1010th minute, then overlap them
Solution:
The picture spans 18\dfrac18 lap on each side of the start. After 600600 seconds Rachel is 3030 seconds short of the line; running 14\dfrac14 lap in 22.522.5 seconds, she is in view between 30−11.25=18.7530-11.25=18.75 and 30+11.25=41.2530+11.25=41.25 seconds of the 1010th minute.
After 600600 seconds Robert is 4040 seconds from the line; running 14\dfrac14 lap in 2020 seconds, he is in view between 3030 and 5050 seconds.
Both appear between 3030 and 41.2541.25 seconds, a window of length 11.2511.25 out of 60,60, so the probability is 11.2560=316.\dfrac{11.25}{60}=\dfrac{3}{16}.
Thus, the correct answer is C.
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