2009 AMC 10A Problem 21

Attempt Problem 21 of the 2009 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

Many Gothic cathedrals have windows with portions containing a ring of congruent circles that are circumscribed by a larger circle. In the figure shown, the number of smaller circles is four. What is the ratio of the sum of the areas of the four smaller circles to the area of the larger circle?

3223 - 2\sqrt{2}

222 - \sqrt{2}

4(322)4(3 - 2\sqrt{2})

12(32)\dfrac{1}{2}(3 - \sqrt{2})

2222\sqrt{2} - 2

Answer: C
Concepts:tangent circlesarea ratiorationalizing denominator
Difficulty rating: 1690
Solution:

Let each small circle have radius 1.1. Their centers form a square of side 2,2, whose diagonal is 22.2\sqrt2.

The large circle's diameter is 2+22,2 + 2\sqrt2, so its radius is 1+2.1 + \sqrt2.

The desired ratio is 4π(1)2π(1+2)2=43+22=4(322). \begin{aligned} \dfrac{4 \cdot \pi (1)^2}{\pi (1 + \sqrt2)^2} &= \dfrac{4}{3 + 2\sqrt2} \\ &= 4(3 - 2\sqrt2). \end{aligned}

Thus, the correct answer is C.

← Problem 20#20
Full Exam

Problem 21 in Other Years