2007 AMC 10B Problem 18

Attempt Problem 18 of the 2007 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

A circle of radius 11 is surrounded by 44 circles of radius rr as shown. What is r?r?
2\sqrt2
1+21+\sqrt2
6\sqrt6
33
2+22+\sqrt2
Answer: B
Concepts:tangent circlessquare (geometry)quadratic
Small hint:
Connect the centers of the four outer circles to form a square
Big hint:
The square has side 2r2r and diagonal 2+2r2+2r
Solution:
Connect the centers of the four outer circles to form a square. Adjacent outer circles are tangent, so each side has length 2r.2r.
The diagonal of the square passes through the center of the central circle, giving length 1+r+r+1=2+2r.1+r+r+1=2+2r. Since a square with side 2r2r has diagonal 2r2,2r\sqrt2, we get 2(2r)2=(2+2r)2.2(2r)^2=(2+2r)^2.
Expanding gives 1+2r+r2=2r2,1+2r+r^2=2r^2, so r2−2r−1=0.r^2-2r-1=0. The positive root is r=1+2.r=1+\sqrt2.
Thus, the correct answer is B.
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