2024 AMC 8 第 2 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

2.

下列表达式写成小数是多少? 4411+11044+441100 \frac{44}{11} + \frac{110}{44} + \frac{44}{1100}

What is the value of this expression in decimal form? 4411+11044+441100 \frac{44}{11} + \frac{110}{44} + \frac{44}{1100}

6.46.4

6.5046.504

6.546.54

6.96.9

6.946.94

答案:C
知识点:分数小数
难度评级:450
视频讲解:
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文字解答:

提出公因数 1111 后,4411\dfrac{44}{11} 化为 4411044\dfrac{110}{44} 化为 104=52=2.5\dfrac{10}{4} = \dfrac{5}{2} = 2.5,而 441100\dfrac{44}{1100} 化为 4100=0.04\dfrac{4}{100} = 0.04。因此 4+2.5+0.04=6.544 + 2.5 + 0.04 = 6.54

所以正确答案是 C

We can simplify the fractions by taking out the common factor 1111: 4411 \dfrac{44}{11} simplifies to 4 4 , 11044 \dfrac{110}{44} simplifies to 104=52=2.5 \dfrac{10}{4} = \dfrac{5}{2} = 2.5 , and 441100 \dfrac{44}{1100} simplifies to 4100=0.04 \dfrac{4}{100} = 0.04 . Therefore, we have 4+2.5+0.04=6.54. 4 + 2.5 + 0.04 = 6.54.

Thus, C is the correct answer.

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