2017 AMC 8 第 17 题

先试着解答 2017 AMC 8 第 17 题,然后核对你的答案与视频与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2017 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

17.

我有一些金币和一些空宝箱。我试着每个宝箱放 99 枚金币,但这样会剩下 22 个宝箱空着。于是我改为每个宝箱放 66 枚金币,但这样会剩下 33 枚金币。我有多少枚金币?
Starting with some gold coins and some empty treasure chests, I tried to put 99 gold coins in each treasure chest, but that left 22 treasure chests empty. So instead I put 66 gold coins in each treasure chest, but then I had 33 gold coins left over. How many gold coins did I have?
99
2727
4545
6363
8181
答案:C
知识点:方程组
小提示:
设宝箱数为 nn
Let nn be the number of treasure chests.
大提示:
为每箱 99 枚的尝试和每箱 66 枚的尝试分别写方程
Write one equation for the 99-coins attempt and another for the 66-coins attempt.
视频讲解:
解答视频缩略图
Play video

Click to load, then click again to play

文字解答:
设宝箱数为 nn,金币数为 gg。那么 9(n−2)=g 9(n - 2) = g 且 6n+3=g。 6n + 3 = g\text{。}解这个方程组得 n=7n = 7,所以金币数为 6⋅7+3=456 \cdot 7 + 3 = 45。
所以正确答案是 C。
Let nn be the number of treasure chests and gg be the number of gold coins. Then 9(n−2)=g9(n - 2) = g and 6n+3=g.6n + 3 = g. Solving this system yields n=7,n = 7, so the number of gold coins is 6⋅7+3=45.6 \cdot 7 + 3 = 45.
Thus, C is the correct answer.
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.