2007 AMC 8 第 1 题

先试着解答 2007 AMC 8 第 1 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2007 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

Theresa 的父母同意,如果她平均每周花 1010 小时帮忙做家务,连续 66 周,就给她买票去看她最喜欢的乐队。前 55 周她分别帮忙 88、1111、77、1212 和 1010 小时。为了得到门票,最后一周她必须工作多少小时?
Theresa’s parents have agreed to buy her tickets to see her favorite band if she spends an average of 1010 hours per week helping around the house for 66 weeks. For the first 55 weeks she helps around the house for 8,8, 11,11, 7,7, 1212 and 1010 hours. How many hours must she work for the final week to earn the tickets?
99
1010
1111
1212
1313
答案:D
知识点:平均数
小提示:
求六周总共需要多少小时
Find the total number of hours needed over all six weeks.
大提示:
将这个总数与 Theresa 前五周已经工作的小时数比较
Compare that total with the hours Theresa already worked in the first five weeks.
解答:
前 55 周 Theresa 总共工作 8+11+7+12+10=488+11+7+12+10=48 小时。
她承诺总共工作 10⋅6=6010\cdot 6=60 小时。
因此她最后一周必须工作 60−48=1260-48=12 小时才能得到门票。
所以正确答案是 D。
During the first 55 weeks, Theresa works for a total of 8+11+7+12+10=488+11+7+12+10=48 hours.
She promised to work 10⋅6=6010\cdot 6=60 hours in all.
This means that she has to work 60−48=1260-48=12 hours during the final week to earn the tickets.
Thus, D is the correct answer.
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