2004 AMC 8 第 18 题

先试着解答 2004 AMC 8 第 18 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2004 AMC 8 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

18.

五个朋友参加飞镖比赛。每人向同一个圆形靶子投两支飞镖,每个人的得分是击中区域分数之和。靶子区域的分数是整数 111010,十次投掷击中的区域分值互不相同。得分为:Alice 1616 分,Ben 44 分,Cindy 77 分,Dave 1111 分,Ellen 1717 分。谁击中了分值为 66 的区域?

Five friends compete in a dart-throwing contest. Each one has two darts to throw at the same circular target, and each individual's score is the sum of the scores in the target regions that are hit. The scores for the target regions are the whole numbers 11 through 10.10. Each throw hits the target in a region with a different value. The scores are: Alice 1616 points, Ben 44 points, Cindy 77 points, Dave 1111 points, and Ellen 1717 points. Who hits the region worth 66 points?

Alice\text{Alice}

Ben\text{Ben}

Cindy\text{Cindy}

Dave\text{Dave}

Ellen\text{Ellen}

答案:A
知识点:逻辑推理分类讨论
难度评级:1400
解答:

Ben 得到四分的唯一方式是 1133,因为他不能两次击中 22

Cindy 的得分可以由 1+6,2+5,3+4. 1 + 6,\quad 2 + 5,\quad 3 + 4. 得到。Ben 已经击中了 1133,所以 Cindy 必须击中 2255

同理,Dave 必须击中 4477。最后,因为 77 已经被使用,Alice 被迫击中 661010,Ellen 击中 8899

所以正确答案是 A

The only way to get Ben's score is with a 11 and 33 since he can't hit 22 twice.

Cindy can achieve her score with 1+6,2+5,3+4. 1 + 6,\quad 2 + 5,\quad 3 + 4. Ben already hit 11 and 3,3, so Cindy must have hit 22 and 5.5.

Similarly, Dave must have hit 44 and 7.7. Finally, since 77 is already used, Alice is forced to have hit 66 and 1010 with Ellen hitting 88 and 9.9.

Thus, A is the correct answer.

← 第 17 题#17
完整试卷

其他年份的第 18 题

1985 AMC 8 · 1986 AMC 8 · 1987 AMC 8 · 1988 AMC 8 · 1989 AMC 8 · 1990 AMC 8 · 1991 AMC 8 · 1992 AMC 8 · 1993 AMC 8 · 1994 AMC 8 · 1995 AMC 8 · 1996 AMC 8 · 1997 AMC 8 · 1998 AMC 8 · 1999 AMC 8 · 2000 AMC 8 · 2001 AMC 8 · 2002 AMC 8 · 2003 AMC 8 · 2005 AMC 8 · 2006 AMC 8 · 2007 AMC 8 · 2008 AMC 8 · 2009 AMC 8 · 2010 AMC 8 · 2011 AMC 8 · 2012 AMC 8 · 2013 AMC 8 · 2014 AMC 8 · 2015 AMC 8 · 2016 AMC 8 · 2017 AMC 8 · 2018 AMC 8 · 2019 AMC 8 · 2020 AMC 8 · 2022 AMC 8 · 2023 AMC 8 · 2024 AMC 8 · 2025 AMC 8 · 2026 AMC 8