2002 AMC 8 Problem 18

Below is the professionally curated solution for Problem 18 of the 2002 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 8 solutions, or check the answer key.

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Concepts:meanunit conversion

Difficulty rating: 1360

18.

Gage skated 11 hr 1515 min each day for 55 days and 11 hr 3030 min each day for 33 days. How long would he have to skate the ninth day in order to average 8585 minutes of skating each day for the entire time?

11 hr

11 hr 1010 min

11 hr 2020 min

11 hr 4040 min

22 hr

Solution:

Gage has skated a total of 575+390=645 min. 5 \cdot 75 + 3 \cdot 90 = 645 \text{ min.}

For an average of 8585 minutes over 99 days, Gage must have skated a total of 859=765 min. 85 \cdot 9 = 765 \text{ min.}

This means that Gage must skate 765645=120 min. 765 - 645 = 120 \text{ min.} on the last day. Note that 120120 minutes is the same as 22 hours.

Thus, E is the correct answer.

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