2022 AMC 8 Problem 3
Attempt Problem 3 of the 2022 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
3.
When three positive integers and are multiplied together, their product is Suppose In how many ways can the numbers be chosen?
Small hint:
The smallest number must be a factor of
Big hint:
Try possible values of with
Solution:
Since and , we have , so . Also must divide , so .
If , the pairs are . If , the only possible pair is . If , then , and there is no integer with .
There are possible triples.
Thus, the correct answer is E.
Problem 3 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
- 1992 AMC 8
- 1993 AMC 8
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- 1998 AMC 8
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