2020 AMC 8 Problem 8
Attempt Problem 8 of the 2020 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
8.
Ricardo has coins, some of which are pennies (-cent coins) and the rest of which are nickels (-cent coins). He has at least one penny and at least one nickel. What is the difference in cents between the greatest possible and least possible amounts of money that Ricardo can have?
Answer: C
Small hint:
Leave one coin of each type fixed
Big hint:
Changing one penny to one nickel changes the value by cents
Video solution:
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Written solution:
The greatest value occurs with nickels and penny, while the least occurs with nickel and pennies.
Between these two cases, pennies have been replaced by nickels. Each replacement adds cents, so the difference is cents.
Thus, the correct answer is C.
Problem 8 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
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