2019 AMC 8 Problem 3

Attempt Problem 3 of the 2019 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Which of the following is the correct order of the fractions 1511,\dfrac{15}{11}, 1915,\dfrac{19}{15}, and 1713,\dfrac{17}{13}, from least to greatest?
1511<1713<1915\dfrac{15}{11} \lt \dfrac{17}{13} \lt \dfrac{19}{15}
1511<1915<1713\dfrac{15}{11} \lt \dfrac{19}{15} \lt \dfrac{17}{13}
1713<1915<1511\dfrac{17}{13} \lt \dfrac{19}{15} \lt \dfrac{15}{11}
1915<1511<1713\dfrac{19}{15} \lt \dfrac{15}{11} \lt \dfrac{17}{13}
1915<1713<1511\dfrac{19}{15} \lt \dfrac{17}{13} \lt \dfrac{15}{11}
Answer: E
Concepts:fraction
Small hint:
Subtract 11 from each fraction
Big hint:
Compare 411,\frac{4}{11}, 413,\frac{4}{13}, and 415\frac{4}{15}
Video solution:
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Written solution:
We can rewrite the fraction as follows: 1511=1+4111713=1+4131915=1+415.\begin{align*} \dfrac{15}{11} &= 1 + \dfrac{4}{11} \\ \dfrac{17}{13} &= 1 + \dfrac{4}{13} \\ \dfrac{19}{15} &= 1 + \dfrac{4}{15}. \end{align*}
Recall that if two fractions have the same numerator, then the fraction with the larger denominator is smaller.
Using this fact, we can see that the correct ordering is 1915<1713<1511. \dfrac{19}{15} \lt \dfrac{17}{13} \lt \dfrac{15}{11}.
Thus, the correct answer is E.
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