2016 AMC 8 Problem 9

Attempt Problem 9 of the 2016 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

What is the sum of the distinct prime integer divisors of 2016?2016?
9 9
12 12
16 16
49 49
63 63
Answer: B
Concepts:prime factorization
Small hint:
Factor 20162016 into primes.
Big hint:
The word “distinct” means to count each prime divisor only once.
Video solution:
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Written solution:
We can prime factorize 20162016 as 25⋅32⋅7.2^5 \cdot 3^2 \cdot 7. This shows that the prime divisors of 20162016 are 2,2, 3,3, and 7.7. The sum of these is 12,12, so B is the correct answer.
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