2015 AMC 8 Problem 3

Attempt Problem 3 of the 2015 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Jack and Jill are going swimming at a pool that is one mile from their house. They leave home simultaneously. Jill rides her bicycle to the pool at a constant speed of 1010 miles per hour. Jack walks to the pool at a constant speed of 44 miles per hour. How many minutes before Jack does Jill arrive?
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Answer: D
Concepts:distance rate and time
Small hint:
Find how many minutes each person takes to travel one mile.
Big hint:
Subtract Jill’s travel time from Jack’s travel time.
Video solution:
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Written solution:
Jack travels at a rate of 44 miles per 6060 minutes. Therefore, it takes him 604=15\dfrac{60}{4} = 15 minutes to get to the pool.
Jill travels at a rate of 1010 miles per 6060 minutes. Therefore it takes her 6010=6\dfrac{60}{10} = 6 minutes to get to the pool.
Therefore, the difference in their times is 15−6=915-6 = 9 minutes.
Thus, the correct answer is D .
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