2012 AMC 8 Problem 9

Attempt Problem 9 of the 2012 AMC 8 below, then check your answer against the video solution and professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 8 solutions, or check the answer key.

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9.

The Fort Worth Zoo has a number of two-legged birds and a number of four-legged mammals. On one visit to the zoo, Margie counted 200 heads and 522 legs. How many of the animals that Margie counted were two-legged birds?

61 61

122 122

139 139

150 150

161 161

Answer: C
Concepts:system of equations
Difficulty rating: 1100
Video solution:
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Written solution:

Let ff be the number of animals with 44 legs and let tt be the number of animals with 22 legs.

Counting the number of legs yields 2t+4f=5222t+4f = 522 and counting the number of heads yields t+f=200.t + f = 200. This means 4t+4f=800,4t+4f = 800, and subtracting the first equation from the second yields 2t=278    t=139.2t = 278 \implies t = 139. This means there are 139139 two-legged birds.

Thus, the answer is C .

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