2003 AMC 8 Problem 3 — Solution | LIVE by Po-Shen Loh

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2003 AMC 8 Problem 3

Attempt Problem 3 of the 2003 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

A burger at Ricky C's weighs $120$ grams, of which $30$ grams are filler. What percent of the burger is not filler?

$60 \%$

$65 \%$

$70 \%$

$75 \%$

$90 \%$

Answer: D

Concepts:percentage

Difficulty rating: 560

Solution:

We get that $120 - 30 = 90$ grams are not filler. The percentage is therefore $100 \cdot \dfrac{90}{120} = 100 \cdot \dfrac{3}{4} = 75 \%.$

Thus, D is the correct answer.

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