2003 AMC 8 Problem 3

Attempt Problem 3 of the 2003 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

A burger at Ricky C’s weighs 120120 grams, of which 3030 grams are filler. What percent of the burger is not filler?
60%60 \%
65%65 \%
70%70 \%
75%75 \%
90%90 \%
Answer: D
Concepts:percentage
Small hint:
First find how many grams are not filler.
Big hint:
Compare the non-filler grams to 120.120.
Solution:
We get that 120−30=90120 - 30 = 90 grams are not filler. The percentage is therefore 100⋅90120=100⋅34=75%. 100 \cdot \dfrac{90}{120} = 100 \cdot \dfrac{3}{4} = 75 \%.
Thus, D is the correct answer.
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