2000 AMC 8 Problem 8
Attempt Problem 8 of the 2000 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 8 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
8.
Three dice with faces numbered through are stacked as shown. Seven of the eighteen faces are visible, leaving eleven faces hidden (back, bottom, between). The total number of dots NOT visible in this view is
Answer: D
Small hint:
Each die has total dots
Big hint:
Subtract the visible dots from the total on all three dice
Solution:
The sum of the numbers on one die is Therefore, the sum of the numbers on all dice is
The visible numbers add up to This makes the sum of the unseen numbers
Thus, D is the correct answer.
Problem 8 in other years
- 1985 AMC 8
- 1986 AMC 8
- 1987 AMC 8
- 1988 AMC 8
- 1989 AMC 8
- 1990 AMC 8
- 1991 AMC 8
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