1996 AMC 8 Problem 8

Attempt Problem 8 of the 1996 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1996 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

Points AA and BB are 1010 units apart. Points BB and CC are 44 units apart. Points CC and DD are 33 units apart. If AA and DD are as close as possible, then the number of units between them is
00
33
99
1111
1717
Answer: B
Concepts:optimization
Small hint:
Place all the points on one line so that CC and DD are pulled back toward AA
Big hint:
With everything collinear, AD=AB−BC−CDAD = AB - BC - CD
Solution:
The distance is smallest when the points are collinear with CC and DD toward A:A: take A=0,A = 0, B=10,B = 10, C=6,C = 6, D=3.D = 3.
Then AD=10−4−3=3.AD = 10 - 4 - 3 = 3.
Thus, the correct answer is B .
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