1996 AMC 8 Problem 3

Attempt Problem 3 of the 1996 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1996 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The 6464 whole numbers from 11 through 6464 are written, one per square, on a checkerboard (an 88 by 88 array of 6464 squares). The first 88 numbers are written in order across the first row, the next 88 across the second row, and so on. After all 6464 numbers are written, the sum of the numbers in the four corners will be
130130
131131
132132
133133
134134
Answer: A
Concepts:arithmetic sequence
Small hint:
The first row holds 11 through 8;8; the last row holds 5757 through 6464
Big hint:
The four corners are the first and last numbers of the top row and of the bottom row
Solution:
The first row is 1,2,…,81, 2, \ldots, 8 and the last row is 57,58,…,64.57, 58, \ldots, 64. The four corners are 1,1, 8,8, 57,57, and 64.64.
Their sum is 1+8+57+64=130.1 + 8 + 57 + 64 = 130.
Thus, the correct answer is A .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.