1994 AMC 8 Problem 8

Attempt Problem 8 of the 1994 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

For how many three-digit whole numbers does the sum of the digits equal 25?25?
22
44
66
88
1010
Answer: C
Concepts:digitsmultiset permutations
Small hint:
The largest possible digit sum is 9+9+9=279 + 9 + 9 = 27, so the digits must be close to all 99s
Big hint:
Find the digit combinations that sum to 2525, then count how many arrangements each has
Solution:
Since the digits sum to 2525 and the maximum is 2727, at least one digit is 99. The possible digit sets are {9,9,7}\{9, 9, 7\} and {9,8,8}.\{9, 8, 8\}.
Each set has 33 distinct arrangements (997,997, 979,979, 799799 and 988,988, 898,898, 889889), giving 66 numbers in all.
Thus, the correct answer is C .
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