1994 AMC 8 Problem 3

Attempt Problem 3 of the 1994 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Each day Maria must work 88 hours. This does not include the 4545 minutes she takes for lunch. If she begins working at 7:257{:}25 A.M. and takes her lunch break at noon, then her working day will end at
3:403{:}40 P.M.
3:553{:}55 P.M.
4:104{:}10 P.M.
4:254{:}25 P.M.
4:404{:}40 P.M.
Answer: C
Concepts:clock
Small hint:
The workday spans 88 hours of work plus the 4545-minute lunch break
Big hint:
Add 88 hours to 7:257{:}25 A.M., then add 4545 more minutes
Solution:
Eight hours after 7:257{:}25 A.M. is 3:253{:}25 P.M.
Adding the 4545-minute lunch break gives an ending time of 4:104{:}10 P.M.
Thus, the correct answer is C .
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