1994 AMC 8 Problem 14

Attempt Problem 14 of the 1994 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

Two children at a time can play pairball. For 9090 minutes, with only two children playing at one time, five children take turns so that each one plays the same amount of time. The number of minutes each child plays is
99
1010
1818
2020
3636
Answer: E
Concepts:rate
Small hint:
With two children playing for the whole 9090 minutes, the total playing time is 2×902 \times 90 child-minutes
Big hint:
Divide the total playing time equally among the 55 children
Solution:
Two children play at every moment for 9090 minutes, so the total playing time is 2×90=1802 \times 90 = 180 child-minutes.
Split equally among 55 children, each plays 1805=36\dfrac{180}{5} = 36 minutes.
Thus, the correct answer is E .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.