1992 AMC 8 Problem 9

Attempt Problem 9 of the 1992 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

The population of a small town is 480.480. The graph indicates the numbers of females and males in the town, but the vertical scale values are omitted. The bars labeled FF and MM represent females and males, respectively. How many males live in the town?
120120
160160
200200
240240
360360
Answer: B
Concepts:ratio and proportion
Small hint:
Let the number of males be MM; then the number of females is 2M2M
Big hint:
Since M+2M=480,M + 2M = 480, solve 3M=4803M = 480
Solution:
If there are MM males, then there are 2M2M females, and together M+2M=480.M + 2M = 480.
So 3M=480,3M = 480, giving M=160.M = 160.
Thus, the correct answer is B .
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