1988 AMC 8 Problem 3 — Solution | LIVE by Po-Shen Loh

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1988 AMC 8 Problem 3

Attempt Problem 3 of the 1988 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

What is the value of the following expression?

$\dfrac{1}{10} + \dfrac{2}{20} + \dfrac{3}{30}$

$.1$

$.123$

$.2$

$.3$

$.6$

Answer: D

Concepts:fraction

Difficulty rating: 450

Solution:

Each fraction equals $\dfrac{1}{10} = .1,$ since $\dfrac{2}{20} = \dfrac{3}{30} = \dfrac{1}{10}.$

So the sum is $.1 + .1 + .1 = .3.$

Thus, the correct answer is D .

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