1988 AMC 8 Problem 3

Attempt Problem 3 of the 1988 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The value of
110+220+330\dfrac{1}{10} + \dfrac{2}{20} + \dfrac{3}{30}
is
0.10.1
0.1230.123
0.20.2
0.30.3
0.60.6
Answer: D
Concepts:fraction
Small hint:
Each fraction reduces to the same value
Big hint:
220=110\dfrac{2}{20} = \dfrac{1}{10} and 330=110\dfrac{3}{30} = \dfrac{1}{10}
Solution:
Each fraction equals 110=0.1,\dfrac{1}{10} = 0.1, since 220=330=110.\dfrac{2}{20} = \dfrac{3}{30} = \dfrac{1}{10}.
So the sum is 0.1+0.1+0.1=0.3.0.1 + 0.1 + 0.1 = 0.3.
Thus, the correct answer is D .
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