2022 AMC 12A Problem 8

Attempt Problem 8 of the 2022 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

The infinite product
103⋅1033⋅10333⋯\sqrt[3]{10}\cdot\sqrt[3]{\sqrt[3]{10}}\cdot\sqrt[3]{\sqrt[3]{\sqrt[3]{10}}}\cdots
evaluates to a real number. What is that number?
10\sqrt{10}
1003\sqrt[3]{100}
10004\sqrt[4]{1000}
1010
1010310\sqrt[3]{10}
Answer: A
Concepts:exponentgeometric sequence
Small hint:
Write every factor as a power of 1010
Big hint:
The exponents are 13,19,127,…,\dfrac13,\dfrac19,\dfrac1{27},\ldots, a geometric series
Solution:
The kkth factor is 1010 raised to the kk-fold cube root, namely 1013k.10^{\frac{1}{3^k}}.
The product is 1010 raised to 13+19+127+⋯=131−13=12. \begin{aligned} &\frac13+\frac19+\frac1{27}+\cdots=\frac{\frac{1}{3}}{1-\frac{1}{3}} \\ &=\frac12. \end{aligned}
So the value is 1012=10.10^{\frac{1}{2}}=\sqrt{10}.
Thus, the correct answer is A.
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