1999 AMC 12 Problem 12

Attempt Problem 12 of the 1999 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 12 solutions, or check the answer key.

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12.

What is the maximum number of points of intersection of the graphs of two different fourth degree polynomial functions y=p(x)y = p(x) and y=q(x),y = q(x), each with leading coefficient 1?1?

11

22

33

44

88

Answer: C
Concepts:polynomialcounting intersections
Difficulty rating: 1510
Solution:

The xx-coordinates of the intersection points are the roots of p(x)q(x).p(x) - q(x). Because both leading coefficients are 1,1, the x4x^4 terms cancel, so p(x)q(x)p(x) - q(x) has degree at most 33 and therefore at most 33 roots. The bound is attainable, for example by taking p(x)=x4p(x) = x^4 and q(x)=x4x(x1)(x+1),q(x) = x^4 - x(x-1)(x+1), whose graphs intersect at x=1,0,1.x = -1, 0, 1.

Thus, the correct answer is C.

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