1997 AMC 12 Problem 16

Attempt Problem 16 of the 1997 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

The three row sums and the three column sums of the array [492816357] \begin{bmatrix} 4&9&2\\ 8&1&6\\ 3&5&7 \end{bmatrix} are the same. What is the least number of entries that must be altered to make all six sums different from one another?
11
22
33
44
55
Answer: D
Concepts:arraysinvariantsconstruction
Small hint:
With only three altered entries, examine the rows and columns containing no alteration
Big hint:
For an upper bound, try changing four entries so that their row and column effects are all distinct
Solution:
With at most three alterations, either two of the six lines are unchanged, or some altered entry is the only alteration in both its row and its column. In the first case those two sums remain equal; in the second, that entry changes its row sum and column sum by the same amount, so those two sums remain equal. Four suffice: replace 4,4, 1,1, 2,2, 66 by 5,5, 3,3, 7,7, 9,9, respectively. The resulting row sums are 21,21, 20,20, 1515 and column sums are 16,16, 17,17, 23.23. Hence the minimum is 4,4, and D is correct.
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