1953 AMC 12 Problem 48

Attempt Problem 48 of the 1953 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1953 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

48.

If the larger base of an isosceles trapezoid equals a diagonal and the smaller base equals the altitude, then the ratio of the smaller base to the larger base is:
12\frac{1}{2}
23\frac{2}{3}
34\frac{3}{4}
35\frac{3}{5}
25\frac{2}{5}
Answer: D
Concepts:isosceles trapezoidPythagorean theoremratio
Small hint:
A diagonal’s horizontal projection is half the sum of the two bases
Big hint:
Scale the larger base to 11, and let the smaller base and altitude both be rr
Solution:
Let the larger base be 1,1, and let the smaller base and altitude both be r.r. A diagonal has horizontal projection 1+r2\frac{1+r}{2} and length 1.1. Thus 1=r2+(1+r2)2. 1=r^2+\left(\frac{1+r}{2}\right)^2. This simplifies to 5r2+2r−3=(5r−3)(r+1)=0. \begin{aligned} 5r^2+2r-3&=(5r-3)(r+1)\\ &=0. \end{aligned} The positive ratio is r=35.r=\frac{3}{5}.
Thus, the correct answer is D.
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