2009 AMC 10A Problem 18

Attempt Problem 18 of the 2009 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

At Jefferson Summer Camp, 60%60\% of the children play soccer, 30%30\% of the children swim, and 40%40\% of the soccer players swim. To the nearest whole percent, what percent of the non-swimmers play soccer?
30%30\%
40%40\%
49%49\%
51%51\%
70%70\%
Answer: D
Concepts:percentageVenn Diagramconditional probability
Small hint:
Assume 100100 children and count soccer players who swim
Big hint:
Find how many of the 7070 non-swimmers play soccer
Solution:
Take 100100 children: 6060 play soccer, and 40%40\% of them, or 24,24, also swim. So 60−24=3660 - 24 = 36 soccer players do not swim.
There are 3030 swimmers and 7070 non-swimmers, so the fraction of non-swimmers who play soccer is 3670≈0.514≈51%.\dfrac{36}{70} \approx 0.514 \approx 51\%.
Thus, the correct answer is D.
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