2001 AMC 10 Problem 23

Attempt Problem 23 of the 2001 AMC 10 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

A box contains exactly five chips, three red and two white. Chips are randomly removed one at a time without replacement until all the red chips are drawn or all the white chips are drawn. What is the probability that the last chip drawn is white?
310\dfrac{3}{10}
25\dfrac25
12\dfrac12
35\dfrac35
710\dfrac{7}{10}
Answer: D
Concepts:sampling without replacementbasic probabilitysymmetry
Small hint:
Imagine drawing all five chips; the game stops when one color is exhausted
Big hint:
The last drawn chip is white exactly when the very last of all five chips is red
Solution:
Imagine drawing all five chips in a random order. The drawing stops on a white chip exactly when both white chips come out before all three reds, which happens precisely when the very last chip in the full ordering is red.
That probability is 35.\dfrac{3}{5}. Thus, the correct answer is D.
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