2006 AMC 8 第 7 题

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7.

XX 的半径为 π\pi。圆 YY 的周长为 8π8 \pi。圆 ZZ 的面积为 9π9 \pi。按半径从小到大排列这些圆。

Circle XX has a radius of π.\pi. Circle YY has a circumference of 8π.8 \pi. Circle ZZ has an area of 9π.9 \pi. List the circles in order from smallest to largest radius.

X,Y,ZX, Y, Z

Z,X,YZ, X, Y

Y,X,ZY, X, Z

Z,Y,XZ, Y, X

X,Z,YX, Z, Y

答案:B
知识点:圆周长圆面积
难度评级:960
解答:

公式为 C=2πrC = 2 \pi rA=πr2A = \pi r^2。由此圆 YY 的半径是 8π÷(2π)=4. 8 \pi \div (2 \pi) = 4. ZZ 的半径是 9π÷π=3. \sqrt{9 \pi \div \pi} = 3. 因为 π\pi 大于 33 且小于 44,所以正确顺序为 Z,X,YZ,X,Y

所以正确答案是 B

Recall that C=2πrC = 2 \pi r and A=πr2.A = \pi r^2. Using these formulas we get that the radius of YY is 8π÷(2π)=4. 8 \pi \div (2 \pi) = 4. We also get that the radius of ZZ is 9π÷π=3. \sqrt{9 \pi \div \pi} = 3. As π\pi is greater than 33 and less than 4,4, the correct order is Z,X,Y.Z,X,Y.

Thus, the answer is B .

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