1992 AMC 8 第 8 题

先试着解答 1992 AMC 8 第 8 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1992 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

一位店主买入 15001500 支铅笔,每支价格为 $0.10\$0.10。如果他以每支 $0.25\$0.25 出售,那么他必须卖出多少支,才能恰好获利 $100.00\$100.00?
A store owner bought 15001500 pencils at $0.10\$0.10 each. If he sells them for $0.25\$0.25 each, how many of them must he sell to make a profit of exactly $100.00?\$100.00?
400400
667667
10001000
15001500
19001900
答案:C
知识点:钱币
小提示:
先求 15001500 支铅笔的总成本。
First find the total cost of the 15001500 pencils
大提示:
收入必须等于成本加 $100\$100;再用所需收入除以每支 $0.25\$0.25 的售价。
The revenue must be the cost plus $100;\$100; divide that needed revenue by the $0.25\$0.25 price
解答:
铅笔成本为 1500×$0.10=$1501500 \times \$0.10 = \$150。要获利 $100\$100,收入必须是 $150+$100=$250\$150 + \$100 = \$250。
每支售价 $0.25\$0.25,所以必须卖出 $250$0.25=1000\dfrac{\$250}{\$0.25} = 1000 支。
所以正确答案是 C。
The pencils cost 1500×$0.10=$150.1500 \times \$0.10 = \$150. To make a $100\$100 profit, the revenue must be $150+$100=$250.\$150 + \$100 = \$250.
At $0.25\$0.25 each, he must sell $250$0.25=1000\dfrac{\$250}{\$0.25} = 1000 pencils.
Thus, the correct answer is C .
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