1986 AMC 8 第 18 题

先试着解答 1986 AMC 8 第 18 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1986 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

18.

一个矩形牧场要用一段 100100 米石墙作为第四边,只在另外三边围栅栏。栅栏上每隔 1212 米立一个柱子,包括栅栏与石墙相接处的两个柱子。围出一个 3636 米乘 6060 米的区域,最少需要多少根柱子?
A rectangular grazing area is to be fenced off on three sides using part of a 100100 meter rock wall as the fourth side. Fence posts are to be placed every 1212 meters along the fence, including the two posts where the fence meets the rock wall. What is the fewest number of posts required to fence an area 3636 m by 6060 m?
1111
1212
1313
1414
1616
答案:B
知识点:周长最优化植树问题
小提示:
要用最少柱子,让 6060 米边靠墙,这样需要围的长度最短
To use the fewest posts, let the 6060 meter side lie along the wall, so the fenced length is as short as possible
大提示:
栅栏路径长 36+60+36=13236 + 60 + 36 = 132 米;每隔 1212 米放一根柱子,并计算两端
The fenced path is 36+60+36=13236 + 60 + 36 = 132 meters; place a post every 1212 meters, counting both ends
解答:
当石墙作为较长的 6060 米边时,用的柱子最少;此时栅栏覆盖两条 3636 米边和一条 6060 米边,总路径长 36+60+36=13236 + 60 + 36 = 132 米。
每隔 1212 米放一根柱子并包括两端,共用 13212+1=12\dfrac{132}{12} + 1 = 12 根柱子。
所以正确答案是 B。
The fewest posts are used when the wall serves as the longer 6060 meter side, so the fence covers two 3636 meter sides and one 6060 meter side, a path of 36+60+36=13236 + 60 + 36 = 132 meters.
Placing a post every 1212 meters, including both ends, uses 13212+1=12\dfrac{132}{12} + 1 = 12 posts.
Thus, the correct answer is B .
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