2019 AMC 8 第 3 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

下列哪一项把分数 1511,1915\dfrac{15}{11},\dfrac{19}{15}1713\dfrac{17}{13},按从小到大排列正确?

Which of the following is the correct order of the fractions 1511,1915,\dfrac{15}{11},\dfrac{19}{15}, and 1713,\dfrac{17}{13}, from least to greatest?

1511<1713<1915\dfrac{15}{11} \lt \dfrac{17}{13} \lt \dfrac{19}{15}

1511<1915<1713\dfrac{15}{11} \lt \dfrac{19}{15} \lt \dfrac{17}{13}

1713<1915<1511\dfrac{17}{13} \lt \dfrac{19}{15} \lt \dfrac{15}{11}

1915<1511<1713\dfrac{19}{15} \lt \dfrac{15}{11} \lt \dfrac{17}{13}

1915<1713<1511\dfrac{19}{15} \lt \dfrac{17}{13} \lt \dfrac{15}{11}

答案:E
知识点:分数
难度评级:770
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文字解答:

先把三个分数改写为同整数部分加一个分数: 1511=1+4111713=1+4131915=1+415.\begin{align*} \dfrac{15}{11} &= 1 + \dfrac{4}{11} \\ \dfrac{17}{13} &= 1 + \dfrac{4}{13} \\ \dfrac{19}{15} &= 1 + \dfrac{4}{15}. \end{align*}

分子相同的正分数,分母越大,分数越小。

因此正确顺序是 1915<1713<1511. \dfrac{19}{15} \lt \dfrac{17}{13} \lt \dfrac{15}{11}.

正确答案是 E

We can rewrite the fraction as follows: 1511=1+4111713=1+4131915=1+415.\begin{align*} \dfrac{15}{11} &= 1 + \dfrac{4}{11} \\ \dfrac{17}{13} &= 1 + \dfrac{4}{13} \\ \dfrac{19}{15} &= 1 + \dfrac{4}{15}. \end{align*}

Recall that if two fractions have the same numerator, then the fraction with the larger denominator is smaller.

Using this fact, we can see that the correct ordering is 1915<1713<1511. \dfrac{19}{15} \lt \dfrac{17}{13} \lt \dfrac{15}{11}.

Thus, the correct answer is E.

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