1989 AMC 8 第 18 题

先试着解答 1989 AMC 8 第 18 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1989 AMC 8 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

18.

计算器上有一个倒数键,按下它会把当前显示的数换成它的倒数。例如,若显示屏上是 44,按一次该键后显示 0.250.25。如果显示屏上是 3232,至少按几次倒数键才能再次显示 3232?
A calculator has a reciprocal key that replaces the number currently displayed with its reciprocal. For example, if the display shows 44 and the key is pressed, the display becomes 0.25.0.25. If 3232 is currently displayed, what is the fewest number of times the reciprocal key must be pressed so that the display again reads 32?32?
11
22
33
44
55
答案:B
知识点:函数分数
小提示:
按一次会把 3232 变成它的倒数 132\frac{1}{32}。
Pressing the key once turns 3232 into 132\frac{1}{32}
大提示:
一个数的倒数再取倒数,会回到原来的数
The reciprocal of the reciprocal of a number is the number itself
解答:
从 3232 开始,按一次倒数键会得到 132\frac{1}{32}。
再按一次,就是对倒数再取倒数,得到 1132=32\frac{1}{\frac{1}{32}} = 32。所以最少需要按 22 次。
所以正确答案是 B。
Pressing the key once changes 3232 to its reciprocal 132.\frac{1}{32}.
Pressing it a second time takes the reciprocal again, returning to 1132=32.\frac{1}{\frac{1}{32}} = 32. So 22 presses are enough.
Thus, the correct answer is B .
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